Question

Width of a slab is $6cm$ whose $\mu =\frac{3}{2}$. If its rear surface is silvered and object is placed at a distance $28cm$ from the front face. Calculate the final position of the image from the silvered surface.

Answer 1

Given: Width of slab is 6 cm whose $\mu =\frac{3}{2}$. If its rear surface is silvered and object is placed at a distance 28 cm from the front face.

To find the final position of the image from the silvered surface.

Solution:

When an object is placed infront of the glass slab it shift the object in the direction of incident light and form an image at a distance $x$

$x=t[1-{\frac{1}{\mu }}_0]⟹x=6[1-\frac{2}{3}]⟹x=6\times \frac{1}{3}=2cm$

Distance of object from virtual mirror,

$=(28+6)-x=34-x=34-2=32cm$

Virtual mirror will form the image of object at a distance 32 cm behind the actual mirror.

As the virtual mirror is 2 cm from the real mirror.

Therefore the distance of image from actual plane mirror

i.e., 32-2=30 cm infront of the mirror.

Therefore the object is 30 cm behind the mirror.