Question

Will be the area of the semicircle whose radius is 2r

Answer 1

Dear Student,

$$\begin{gathered} \mathrm{Area}\mathrm{of}\mathrm{circle}={\mathrm{\pi r}}^2 \\ \mathrm{Area}\mathrm{of}\mathrm{semi}-\mathrm{circle}=\frac{{\mathrm{\pi r}}^2}{2} \\ \mathrm{Area}\mathrm{of}\mathrm{semi}-\mathrm{circle}=\frac{\mathrm{\pi }{\left(2\mathrm{r}\right)}^2}{2} \\ \mathrm{Area}\mathrm{of}\mathrm{semi}\mathrm{circle}=\frac{4\times \mathrm{\pi }\times {\mathrm{r}}^2}{2} \\ \boxed{\mathbf{Area}\mathbf{}\mathbf{of}\mathbf{}\mathbf{semi}\mathbf{}\mathbf{circle}\mathbf{}\mathbf{=}\mathbf{}\mathbf{2}{\mathbf{\pi r}}^{\mathbf{2}}} \end{gathered}$$
Regards