The reaction will occur is Fe is oxidised to Fe2+.
Fe+2HCl→FeCl2+H2
Writing two half reactions,
Fe→Fe2++2e− Oxdiation;E∘Fe/Fe2+=0.44 volt
2H++2e−→H2Reduction;E∘H+/H=0.0 volt–––––––––––––––––––––––––––––––
Adding; emf=0.44 volt
Since, emf is positive, the reaction shall occur.