Will the configuration be E or Z?

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Solution

(E)- : the higher priority groups are on opposite sides of the double bond.
(Z)- : the higher priority groups are on the same side of the double bond.

The $C H_{3}$ group has the higher priority because its carbon atom has an atomic number of 6 compared with an atomic number of 1 for the hydrogen also attached to the carbon-carbon double bond.The isomer drawn above has the two higher priority groups on opposite sides of the double bond. The compound is (E).

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Element X has electronic configuration 2, 8, 18, 8, 1. Without identifying X,

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(b) write if X will be an oxidising agent or a reducing agent. Why ?

{S N}_{1}

{S N}_{2}

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