Wires 1 and 2 carrying currents i1 and i2 respectively are inclined at an angle θ to each other. The force on a small element ‘dl’ of wire 2 at a distance ‘n’ from the wire 1, as shown in figure, due to the magnetic field of wire 1 is
A
μ02πγi1i2dltanθ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
μ02πγi1i2dlsinθ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
μ02πγi1i2dlcosθ
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
μ02πγi1i2dlsinθ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is Cμ02πγi1i2dlcosθ Now,F1=μ02πI1I2d∴F=μ02πi1i2p.dlcosθ