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Question

Wires 1 and 2 carrying currents i1 and i2 respectively are inclined at an angle θ to each other. The force on a small element ‘dl’ of wire 2 at a distance ‘n’ from the wire 1, as shown in figure, due to the magnetic field of wire 1 is

  1. μ02πγi1 i2 dl tan θ
  2. μ02πγi1 i2 dl sin θ
  3. μ02πγi1 i2 dl cos θ
  4. μ02πγi1 i2 dl sin θ


Solution

The correct option is C μ02πγi1 i2 dl cos θ
Now,F1=μ02πI1I2dF=μ02πi1i2p.dl cos θ

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