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Standard X

Chemistry

Atomic Mass

With 4 mole o...

Question

With 4 mole of KI one mole of ${C l}_{2}$ is treated to yield gas, which is then treated with hypo solution, then correct regarding this is/are:

Equivalent weight of 1/2 is

\frac{M}{1}

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To react completely with product, 1 mole of hypo solution are required

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n-factor of hypo solution is 1

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n-factor of

{C l}_{2}

is 2

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Solution

The correct option is A Equivalent weight of 1/2 is $\frac{M}{1}$

Thus, $n -$ factor of $I_{2} = 2$
To react completely with the product,
${2 N a}_{2} S_{2} O_{3} + I_{2} ⟶ {N a}_{2} S_{4} O_{6} + 2 N a I$
$1$ mole of hype $({N a}_{2} S_{2} O_{3})$ is required.
${2 N a}_{2} S_{2} O_{3} + I_{2} ⟶ {N a}_{2} S_{4} O_{6} + 2 N a I$
$n -$ factor of hype solution $= 1$
$n -$ factor of chlorine $= 2$ .

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With 4 mole of KI one mole of Cl2 is treated to yield gas, which is then treated with hypo solution, then correct regarding this is/are:

The correct option is A Equivalent weight of 1/2 is M1Thus, n−factor of I2=2To react completely with the product,2Na2S2O3+I2⟶Na2S4O6+2NaI1 mole of hype (Na2S2O3) is required.2Na2S2O3+I2⟶Na2S4O6+2NaIn−factor of hype solution =1n−factor of chlorine =2.

With 4 mole of KI one mole of ${C l}_{2}$ is treated to yield gas, which is then treated with hypo solution, then correct regarding this is/are: