Question

With a change in hybridization of the carbon bearing the charge, the stability of a carbanion decreases in the order

• A. $sp<{sp}^2<{sp}^3$
• B. $sp<{sp}^3<{sp}^2$
• C. ${sp}^3<{sp}^2<sp$
• D. ${sp}^2<sp<{sp}^3$

Answer 1

The correct option is C ${sp}^3<{sp}^2<sp$

Stability of carbanions increases with increase in $s-$ character of hybrid orbital of carbon bearing charge hence correct order is:

$s{p}^3<s{p}^2<sp$