With excess of HI or PI 3- 1-2 - ethanediol givesA- EthyleneB- Ethyl iodideC- Ethylidene diiodideD- Ethylene diiodide

The correct option is A Ethylene ...

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With excess of HI or PI₃ , 1, 2 - ethanediol gives

Ethyl iodide

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Ethylidene diiodide

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Ethylene diiodide

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Ethylene

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C H \equiv C H H g S O 4 - --- \to H_{2} S O_{4} (X) L i A l H_{4} - --- \to (Y) P B r_{3} - -- \to (Z)

Z

H C l

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