Question

With excess of water, both $P_2{O}_5$ and $P{Cl}_5$ give:

• A. $H_{3}P{O}_3$
• B. $H_{3}P{O}_2$
• C. $H_{3}P{O}_4$
• D. $H_4{P}_2{O}_7$

Answer 1

Answer: (C)

$H_{3}P{O}_4$

Both $P_2{O}_5$ and $P{Cl}_5$ give $H_{3}P{O}_4$ with excess of water.

$P_2{O}_5+3H_{2}O⟶2H_{3}P{O}_4$

$P{Cl}_5+4H_{2}O⟶H_{3}P{O}_4+5HCl$

Hence, option $C$ is correct.