With increase in frequency of an AC supply, the impedence of an L-C-R series circuit

remains constant

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increases

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decreases

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decreases at first, becomes minimum and then increases

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Solution

The correct option is D decreases at first, becomes minimum and then increases
We have the formula for Impedance

$Z = \sqrt{R^{2} + {(X_{l} - X_{C})}^{2}} X_{C} = \frac{1}{ω C} X_{l} = ω L$

And from the graph it can be easily seen that is $D e c r e a s e s$ first and then $I n c r e a s e s$ .

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With increase in frequency of an AC supply, the impedence of an L-C-R series circuit

The correct option is D decreases at first, becomes minimum and then increasesWe have the formula for Impedance Z=√R2+(Xl−XC)2XC=1ωCXl=ωLAnd from the graph it can be easily seen that is Decreases first and then Increases.

The correct option is D decreases at first, becomes minimum and then increases
We have the formula for Impedance

$Z = \sqrt{R^{2} + {(X_{l} - X_{C})}^{2}} X_{C} = \frac{1}{ω C} X_{l} = ω L$

And from the graph it can be easily seen that is $D e c r e a s e s$ first and then $I n c r e a s e s$ .