The correct option is A True
C is mid-point of the line segment AB.
So, AC=CB
D and E are mid-points of the segments AC and BCrespectively.
So, AD=DC and CE=EB
Since, AC=CB
=> 2AD=2BE
=> AD=BE
Since, AC=AD+DC=AD+AD=2AD
CB=AC=2AD
Now,
AB=AC+CB=2AD+2AD=4AD=4BE
So, AB=4BE