Question

With respect to the roots of $x^2–2x–3=0$, we can say that

• A. roots are not real
• B. both of them are integers
• C. one of the root is zero
• D. both of them are natural numbers

Answer 1

The correct option is B

both of them are integers

Step 1:- For $x^2–2x–3=0$, value of discriminant
$D=(-2{)}^2–4(-3\left)\right(1)=4+12=16$.

Step 2:- Since, D is a perfect square, roots are rational and unequal.

Step 3:- Solving the equation,
$x=\frac{-(-2)+\sqrt{(}16)}{2}or\frac{-(-2)-\sqrt{(}16)}{2}$
$x=3,-1$
Thus, both of them are integers.