With the following informations- determine standard Gibbs free energy of formation of N 2 O 4 g- 1 2 N 2 g- 1 2 O 2 g - NOg - G -86-6 kJ NOg- 1 2 O 2 g - N O 2 g - G -34-82 kJ 2NO 2 g - N 2 O 4 g - G -5-77 kJ

12N_2+12O_2 ⟶ NO.....Δ G_1= 86.6 KJ NO+12O_2 ⟶ NO_2.....Δ G_2= 34.82 KJ 2NO_2 ⟶ N_2O_4.... Δ G_3= 5.77KJ N_2+2O_2 ⟶ N_2O_3....Δ G ⇒ 2 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Heat Capacity

With the foll...

Question

With the following informations, determine standard Gibbs free energy of formation of $N_{2} O_{4} (g)$ .
$\frac{1}{2} N_{2} (g) + \frac{1}{2} O_{2} (g) ⟶ N O (g)$ ${Δ G} = 86.6 k J$
$N O (g) + \frac{1}{2} O_{2} (g) ⟶ N O_{2} (g)$ ${Δ G} = - 34.82 k J$
${2 N O}_{2} (g) ⟶ N_{2} O_{4} (g)$ ${Δ G} = - 5.77 k J$

Open in App

Solution

Suggest Corrections

Similar questions

N_{2} O_{4}

\frac{1}{2} N_{2} (g) + \frac{1}{2} O_{2} (g) \to N O (g)

Δ G^{0}

N O (g) + \frac{1}{2} O_{2} (g) \to \frac{1}{2} N_{2} (g)

Δ G^{0}

2 N O_{2} (g) \to N_{2} O_{4} (g)

Δ G^{0}

K

N_{2} O_{4} (g) ⇌ N_{2} (g) + \frac{1}{2} O_{2} (g)

Δ G = - 177 K c a l

2 F e (s) + \frac{3}{2} O_{2} (g) \to F e_{2} O_{3} (s)

Δ G = - 19 K

4 F e_{2} O_{3} (s) + F e (s) \to 3 F e_{3} O_{4} (s)

F e_{3} O_{4}

\frac{1}{2} N_{2} (g) + \frac{1}{2} O_{2} (g) \to N O (g); △_{r} H^{⊖} = 90 K J M o l^{- 1}

N O (g) + \frac{1}{2} O_{2} (g) \to N O_{2} (g) : △_{r} H^{⊖} = - 74 K J M o l^{- 1}

Δ G = - 177

(1)

2 F e (s) + \frac{3}{2} O_{2} (g) \to F e_{2} O_{3} (s)

Δ G = - 19

(2)

4 F e_{2} O_{3} (s) + F e (s) \to 3 F e_{3} O_{4} (s)

F e_{3} O_{4}

Join BYJU'S Learning Program