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Question

With the help of a car jack, a person lifts a 1.2 tonne car with a force of 5000 N. Calculate the jack’s mechanical advantage. (Take g = 10 m s2)

A
2.40
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B
1.25
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C
0.80
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D
12.50
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Solution

The correct option is A 2.40
Given:

The mass of the car, m=1.2 tonne=1.2×103 kg =1200 kg

Therefore, the force that the car jack has to overcome is equal to the weight of the car, i.e., the load, L=1200×g=1200×10=12,000 N

The effort applied by the person on the jack, E=5000 N

Mechanical advantage of the car jack, MA=LE
=12,0005000=2.40

Therefore, the car jack's mechanical advantage is 2.40.

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