With the help of the figure above, find the value of $cos b$ if $sin a = x$ .

x

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\frac{1}{x}

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| 1 - x |

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\frac{90 - x}{90}

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Solution

The correct option is A $x$
In the given triangle, $a^{o} + b^{o} + 90^{o} = 180^{o}$
$\Rightarrow a = 90 - b$
$\Rightarrow sin a = x$
$\Rightarrow cos b = cos (90 - a) = sin a = x$

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