Question

With the increase in s-character of hybrid orbital, $C-C$ bond length:

• A. decreases
• B. increases
• C. does not change
• D. may increase or decrease

Answer 1

The correct option is A decreases

In $s{p}^3$ hybridization, s character is 25 % and carbon has all single bonds.
In $s{p}^2$ hybridization, s character is 33.33 % and carbon has one double bond.
In $sp$ hybridization, s character is 50 % and carbon has two double bond or one triple bond.
Thus as s character increases single bond changes to double and then triple bond. And bond lengths of single double and triple bond is in the order of:
Single > Double > Triple