Question

With the usual notations, check if the following equation $S_t=u+\frac{1}{2}a(2t-1)$ is dimensionally correct or not.

Answer 1

$LHS$ Dimension, $S=M^0{LT}^0$

$RHS$ Dimension $=\mu +\frac{1}{2}a(2t-1)\Rightarrow M^0{LT}^{-1}$

$LHS\ne RHS$, following equation $S=\mu +\frac{1}{2}(2at-1)$.