Question

With what acceleration 'a' should the box in figure descend so that the block of mass M exerts a force $\frac{Mg}{4}$ on the floor of the box?

• A. $\frac{g}{4}$
• B. $\frac{g}{2}$
• C. $\frac{3g}{4}$
• D. 4g

Answer 1

The correct option is C $\frac{3g}{4}$


F.B.D. of block in the frame of the box is as shown
$Mg=N+Ma$
$Mg=\frac{Mg}{4}+Ma$
$a=\frac{3g}{4}$
$\therefore \left(c\right)$