Question

With what minimum acceleration can a fireman slides down a rope while k breaking strength of the rope is $\frac{2}{3}$ his weight

• A. $\frac{2}{3}g$
• B. $g$
• C. $\frac{1}{3}g$
• D. $Zero$

Answer 1

The correct option is C $\frac{1}{3}g$

When fireman slides down, Tension in the rope T = m(g – a)
For critical condition $m(g-a)=\frac{2}{3}mg\Rightarrow mg-ma=\frac{2}{3}mg\therefore a=\frac{g}{3}$