1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

With what minimum pressure (in kPa), a given volume of an ideal gas (Cp,m=72 R), originally at 400 K and 100 kPa pressure can be compressed irreversibly and adiabatically in order to raise its temperature to 600 K:

A
362.5 kPa
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
275 kPa
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
437.5 kPa
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
550 kPa
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D. 275 kPa.Given,Cp,m=72 RTherefore, Cv=Cp−R=72 R−R=52 R.From the first law of thermodynamics,ΔU=W+Q For an adiabatic irreversible compression, Q = 0. ∴ΔU=WThe change in internal energy is given by, ΔU=nCv,m(T2−T1)and the work done is given by, W=−PextΔV ∴nCv,m(T2−T1)=−Pext(V2−V1) nCv,m(T2−T1)=−P2[nRT2P2−nRT1P1] ⇒52R(T2−T1)=−P2×R[T2P2−T1P1] ⇒P2=275 kPa.

Suggest Corrections
17
Join BYJU'S Learning Program
Related Videos
First Law of Thermodynamics
CHEMISTRY
Watch in App
Join BYJU'S Learning Program