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Question

With what speed a body be thrown upwards so that the distance traversed in $${5}^{th}$$ second and $${6}^{th}$$ seconds are equal?


A
5.84 m/s
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B
49 m/s
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C
98 m/s
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D
98 m/s
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Solution

The correct option is B $$49\ m/s$$

Given,

A body is thrown upward at speed, u

At 5th and 6th distance travel is equal = $$s$$

 

Mean in 4sec to 5 sec distance travel = $$s$$

And in 5sec to 6 sec distance travel = $$s$$

 

It is only possible if body deaccelerated in 4sec to 5 sec and accelerated in 5sec to 6 sec

In projectile motion, this condition is suited, if in 4sec to 5 sec body go upward, and in 5sec to 6 sec body go downward.

 

So, at 5sec body is at top, and its vertical velocity is zero.

Acceleration of gravity, $$g$$

Time, $$t$$

Initial velocity, $$u$$

Final velocity, $$v$$

 

Apply kinematic equation at top position.

$$v=u-gt$$

$$0=u-gt$$

$$u=gt=9.81\times 5=49.01\,\,m/s$$

Hence, body thrown upward at speed $$49\,\,m/s$$ 


978335_1033612_ans_6aeafd99d7f147c29303dbeefacdf15f.png

Physics

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