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Question

With what speed must an object be thrown vertically upwards to reach a height of 91.5 m? (Take a=9.8 ms2)

A
52.3 ms1
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B
49.2 ms1
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C
42.3 ms1
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D
45.7 ms1
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Solution

The correct option is C 42.3 ms1
Let the initial velocity be 'u'.
On reaching the maximum height, final velocity v=0.
Height, s = 91.5 m and acceleration, a=9.8 ms2
Using the third equation of motion,
v2=u2+2as,
02=u22×9.8×91.5
u=42.3 ms1
Therefore the object should be thrown vertically up with a speed of 42.3 ms1

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