With what velocity must an electron travel so that its momentum is equal to that of a photon of wave length $560$ nm?

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Solution

$λ = \frac{h}{m v}$

$v = \frac{h}{m λ}$

$v = \frac{6.6 \times 10^{- 34}}{9.1 \times 10^{- 31} \times 560 \times 10^{- 9}}$

$v = 0.00129513 \times 10^{6}$ m/s

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With what velocity must an electron travel so that its momentum is equal to that of a photon of wave length 560 nm?

λ=hmvv=hmλv=6.6×10−349.1×10−31×560×10−9v=0.00129513×106 m/s

With what velocity must an electron travel so that its momentum is equal to that of a photon of wave length $560$ nm?

$λ = \frac{h}{m v}$

$v = \frac{h}{m λ}$

$v = \frac{6.6 \times 10^{- 34}}{9.1 \times 10^{- 31} \times 560 \times 10^{- 9}}$

$v = 0.00129513 \times 10^{6}$ m/s