Without actual division find whether 1768 has terminating of non-terminating recurring decimal expansion-

68=2×2×17=2^2×17 Since Denominator has 17 and as well as numerator has 17 so, 1768 will terminate as non repeating decimal. ...

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Mathematics

Terminating and Non-Terminating Decimals

Without actua...

Question

Without actual division find whether $\frac{17}{68}$ has terminating of non-terminating recurring decimal expansion?

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Solution

$68 = 2 \times 2 \times 17 = 2^{2} \times 17$
Since Denominator has $17$ and as well as numerator has $17$ so, $\frac{17}{68}$ will terminate as non repeating decimal.

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Without actual division find whether 1768 has terminating of non-terminating recurring decimal expansion?

68=2×2×17=22×17Since Denominator has 17 and as well as numerator has 17 so, 1768 will terminate as non repeating decimal.

Without actual division find whether $\frac{17}{68}$ has terminating of non-terminating recurring decimal expansion?

$68 = 2 \times 2 \times 17 = 2^{2} \times 17$
Since Denominator has $17$ and as well as numerator has $17$ so, $\frac{17}{68}$ will terminate as non repeating decimal.