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Question

Without actual division, show that each of the following rational numbers is a non-terminating repeating decimal:

(i) 1123×3
(ii) 7322×33×5
(iii)12922×57×75
(iv)935
(v)77210
(vi) 32147
(vii) 29343
(viii) 64455

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Solution

(i) 1123 × 3
We know either 2 or 3 is not a factor of 11, so it is in its simplest form.
Moreover, (23 × 3) (2m × 5n)
Hence, the given rational is non-terminating repeating decimal.

(ii) 7322 × 33 ×5
We know 2, 3 or 5 is not a factor of 73, so it is in its simplest form.
Moreover, (22 × 33 × 5)(2m × 5n)
Hence, the given rational is non-terminating repeating decimal.

(iii) 12922 × 57 × 75
We know 2, 5 or 7 is not a factor of 129, so it is in its simplest form.
Moreover, (22 × 57 × 75)(2m × 5n)
Hence, the given rational is non-terminating repeating decimal.

(iv) 935 = 95 × 7
We know either 5 or 7 is not a factor of 9, so it is in its simplest form.
Moreover, (5 × 7) ≠ (2m × 5n)
Hence, the given rational is non-terminating repeating decimal.


(v) 77210 = 77 ÷ 7210 ÷ 7 = 1130 = 112 × 3 × 5
We know 2, 3 or 5 is not a factor of 11, so 1130 is in its simplest form.
Moreover, (2 × 3 × 5)(2m × 5n)
Hence, the given rational is non-terminating repeating decimal.

(vi) 32147 = 323 × 72
We know either 3 or 7 is not a factor of 32, so it is in its simplest form.
Moreover, (3 × 72)(2m × 5n)
Hence, the given rational is non-terminating repeating decimal.

(vii) 29343 = 2973
We know 7 is not a factor of 29, so it is in its simplest form.
Moreover, 73(2m × 5n)
Hence, the given rational is non-terminating repeating decimal.

(viii) 64455 = 645 × 7 × 13
We know 5, 7 or 13 is not a factor of 64, so it is in its simplest form.
Moreover, (5 × 7 × 13)(2m × 5n)
Hence, the given rational is non-terminating repeating decimal.

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