Without actually calculating find which is greater 3111 or 1714

They key to this problem is 17 x 2=34 and 34 gt;31 31¹¹ lt;34¹¹ 34¹¹=(17 x 2)¹¹=17¹¹ x 2¹¹= 17¹¹ x 2⁴ x 2⁴ x 2³ 17¹¹ x 2⁴ x 2⁴ x 2³ lt; 17¹¹ x 17 x 17 x ...

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Standard VII

Mathematics

Multiplication of Integers

Without actua...

Question

Without actually calculating find which is greater

31¹¹or 17¹⁴

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Solution

They key to this problem is 17 x 2=34 and 34>31
31¹¹<34¹¹
34¹¹=(17 x 2)¹¹=17¹¹ x 2¹¹= 17¹¹ x 2⁴ x 2⁴ x 2³
17¹¹ x 2⁴ x 2⁴ x 2³< 17¹¹ x 17 x 17 x 17
17¹¹ x 17 x 17 x 17=17¹⁴

Since 31¹¹<34¹¹ and 34¹¹ = 17¹⁴
therefore 31¹¹<17¹⁴

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Without actually calculating find which is greater 3111 or 1714

They key to this problem is 17 x 2=34 and 34>31 31¹¹<34¹¹ 34¹¹=(17 x 2)¹¹=17¹¹ x 2¹¹= 17¹¹ x 2⁴ x 2⁴ x 2³ 17¹¹ x 2⁴ x 2⁴ x 2³< 17¹¹ x 17 x 17 x 17 17¹¹ x 17 x 17 x 17=17¹⁴ Since 31¹¹<34¹¹ and 34¹¹ = 17¹⁴ therefore 31¹¹<17¹⁴

Without actually calculating find which is greater

31¹¹or 17¹⁴

They key to this problem is 17 x 2=34 and 34>31
31¹¹<34¹¹
34¹¹=(17 x 2)¹¹=17¹¹ x 2¹¹= 17¹¹ x 2⁴ x 2⁴ x 2³
17¹¹ x 2⁴ x 2⁴ x 2³< 17¹¹ x 17 x 17 x 17
17¹¹ x 17 x 17 x 17=17¹⁴

Since 31¹¹<34¹¹ and 34¹¹ = 17¹⁴
therefore 31¹¹<17¹⁴