Without actually performing the long division, state whether 615 will have a terminating decimal expansion or a non-terminating repeating decimal expansion.
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Solution
615
On dividing the numerator and the denominator by 3; we get 25.
Here, denominator is in the form of 2m×5n, where m = 0 and n = 1.
Thus, the decimal expansion of the number 615 is terminating.