Without adding, find the sum of 1 + 3 + 5 + 7 + 9 + 11.
[2 marks]
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Solution
Given the sum of consecutive odd numbers is 1 + 3 + 5 + 7 + 9 + 11.
We know that, Sum of first n odd numbers is n2.
[1 mark]
Number of consecutive odd numbers = 6
Thus, n = 6
Therefore, sum = n2 = 62 = 36
[1 mark]