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Question

Without adding, find the sum of given numbers:

1+3+5+7+9+11+13+15+17+19

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Solution

This is an arithmetic progression whose first term is 1 and the common difference is 2 and number of terms = 10
Sum of an arithmetic progression = n2×(2a+(n1)d)
Therefore, Sum = 102×(2×1+(101)×2)
Sum = 102×20
Sum = 100

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