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Byju's Answer
Standard XII
Mathematics
Cofactor
Without expan...
Question
Without expanding a determinant at any stage
∣
∣ ∣ ∣
∣
x
2
+
x
x
+
1
x
−
2
2
x
2
+
3
x
−
1
3
x
3
x
−
3
x
2
+
2
x
+
3
2
x
−
1
2
x
−
1
∣
∣ ∣ ∣
∣
is of the form
A
x
n
+
B
. Find
n
.
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Solution
Let
Δ
=
∣
∣ ∣ ∣
∣
x
2
+
x
x
+
1
x
−
2
2
x
2
+
3
x
−
1
3
x
3
x
−
3
x
2
+
2
x
+
3
2
x
−
1
2
x
−
1
∣
∣ ∣ ∣
∣
Applying
R
1
→
R
1
+
R
3
−
R
2
∴
Δ
=
∣
∣ ∣ ∣
∣
4
0
0
2
x
2
+
3
x
−
1
3
x
3
x
−
3
x
2
+
2
x
+
3
2
x
−
1
2
x
−
1
∣
∣ ∣ ∣
∣
Applying
C
1
→
C
1
−
C
3
and
C
2
→
C
2
−
C
3
, then
Δ
=
∣
∣ ∣ ∣
∣
4
0
0
2
x
2
+
2
3
3
x
−
3
x
2
+
4
0
2
x
−
1
∣
∣ ∣ ∣
∣
Applying
R
2
→
R
2
−
x
2
2
R
1
and
R
3
→
R
3
−
x
2
4
R
1
, then
Δ
=
∣
∣ ∣
∣
4
0
0
2
3
3
x
−
3
4
0
2
x
−
1
∣
∣ ∣
∣
=
∣
∣ ∣
∣
4
0
0
2
3
3
x
4
0
2
x
∣
∣ ∣
∣
+
∣
∣ ∣
∣
4
0
0
2
3
−
3
4
0
−
1
∣
∣ ∣
∣
=
x
∣
∣ ∣
∣
4
0
0
2
3
3
4
0
2
∣
∣ ∣
∣
+
∣
∣ ∣
∣
4
0
0
2
3
−
3
4
0
−
1
∣
∣ ∣
∣
=
x
A
+
B
∴
n
=
1
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0
Similar questions
Q.
Without expanding at any stage show that
∣
∣ ∣ ∣
∣
x
2
+
x
x
+
1
x
−
2
2
x
2
+
3
x
−
1
3
x
3
x
−
3
x
2
+
2
x
+
3
2
x
−
1
2
x
−
1
∣
∣ ∣ ∣
∣
=
x
A
+
B
where
A
and
B
are determinants of order
3
not involving
x
.
Q.
If
∣
∣ ∣ ∣
∣
x
2
+
x
x
+
1
x
−
2
2
x
2
+
3
x
−
1
3
x
3
x
−
3
x
2
+
2
x
+
3
2
x
−
1
2
x
−
1
∣
∣ ∣ ∣
∣
= Ax+B then
Q.
If
∣
∣ ∣ ∣
∣
x
2
+
x
x
+
1
x
−
2
2
x
2
+
3
x
−
1
3
x
3
x
−
3
x
2
+
2
x
+
3
2
x
−
1
2
x
−
1
∣
∣ ∣ ∣
∣
=
a
x
−
12
, then
a
is equal to
Q.
If
∣
∣ ∣ ∣
∣
x
2
+
x
x
+
1
x
−
2
2
x
2
+
3
x
−
1
3
x
3
x
−
3
x
2
+
2
x
+
3
2
x
−
1
2
x
−
1
∣
∣ ∣ ∣
∣
=
a
x
−
12
,
then value of
a
2
is
Q.
∣
∣ ∣ ∣
∣
x
2
+
x
x
+
1
x
+
2
x
2
+
3
x
−
1
3
x
3
x
−
3
x
2
+
2
x
+
3
2
x
−
1
2
x
−
1
∣
∣ ∣ ∣
∣
=
A
x
+
B
where
A
and
B
are determinants of order
3
. Then
A
+
2
B
is equal to
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