We have,
∣∣ ∣∣x+yy+zz+xzxy111∣∣ ∣∣.
Using operation,
R1→R1+R2
∣∣ ∣∣x+y+zx+y+zx+y+zzxy111∣∣ ∣∣.
x+y+z∣∣ ∣∣111zxy111∣∣ ∣∣.
(x+y+z)×0=0
Hence, this is the answer.