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Question

Without expanding, prove that ∣ ∣x+yy+zz+xzxy111∣ ∣=0.

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Solution

We have,

∣ ∣x+yy+zz+xzxy111∣ ∣.


Using operation,

R1R1+R2

∣ ∣x+y+zx+y+zx+y+zzxy111∣ ∣.

x+y+z∣ ∣111zxy111∣ ∣.

(x+y+z)×0=0


Hence, this is the answer.


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