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Question

Without expanding, prove that
Δ=∣ ∣x+yy+zz+xzxy111∣ ∣=0

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Solution

Applying R1R1+R2 to Δ, we get
Δ=∣ ∣x+y+zx+y+zx+y+zzxy111∣ ∣=0
since the elements of R1 and R3 are proportional, Δ=0

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