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Question

Without expanding the determinant prove that ∣ ∣apbqmcrn∣ ∣+∣ ∣rncqmbpa∣ ∣=0

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Solution

we have
∣ ∣apbqmcrn∣ ∣+∣ ∣rncqmbpua∣ ∣C1C3
=∣ ∣apbqmcrn∣ ∣∣ ∣cnrbmqap∣ ∣C2C3
=∣ ∣apbqmcrm∣ ∣+∣ ∣crnbqmapu∣ ∣

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