Without finding cubes factorise and find the value of (1/4)³+ (1/3)³-(7/12)³

Open in App

Solution

as we know that - if: x+y+z =0
then;
x3 +y3+ z3 =3xyz
here,

1/4+ 1/3+(-7/12) = 0/12=0
So we can simplyfi this as,

= (1/4)³ + (1/3)³+ (-7/12)³= 3(1/4)(1/3)(-7/12)

= -7/48

=0.14583

Hope this helps.
Good luck.

Suggest Corrections

Similar questions

Without actually calculating the cubes, find the value of :

{(\frac{1}{2})}^{3} + {(\frac{1}{3})}^{3} + {(\frac{- 5}{6})}^{3}

{(\frac{1}{2})}^{3} + {(\frac{1}{3})}^{3} - {(\frac{5}{6})}^{3}

Without actually calculating the cubes, find the value of ${(- 12)}^{3} + {(7)}^{3} + {(5)}^{3}$ .

{(\frac{1}{2})}^{3} + {(\frac{1}{3})}^{3} - {(\frac{5}{6})}^{3}

(0.2)^{3} - (0.3)^{3} + (0.1)^{3}

Join BYJU'S Learning Program