Without finding the squares, find the difference:
(a) $68^{2} - 67^{2}$
(b) $1000^{2} - 99^{2}$
(c) $221^{2} - 220^{2}$

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Solution

$(1.) 68^{2} - 67^{2} = (68 + 67) (68 - 67) = 135 (2.) 1000^{2} - 99^{2} = (1000 + 99) (1000 - 99) = 1099 \times 901 = 990, 199 (3.) 221^{2} - 220^{2} = (221 + 220) (221 - 220) = 441 \times 1 = 441$

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P = \frac{V^{2}}{R} = \frac{(220)^{2}}{24}

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k

672

[\begin{matrix} x & y \\ z & u \end{matrix}]

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