wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Without solving the following quadratic equation, find the greater value of p for which the given equation has real and equal roots. x2+(p3)x+p=0.

Open in App
Solution

Given equation x2+(px)x+p=0

Roots are real and equal, then b24ac=0

Here we compare the coefficients of a, b and c with the equation

ax2+bx+c=0.

a=1,b=p3 and c=p

Now putting the values of a, b and c in equation

(p3)24×1×p=0

p2+96p4p=0

p2+910p=0

p210p+9=0

p29pp+9=0

p(p9)1(p9)=0

(p9)(p1)=0

Hence, p=9 or 1.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Nature and Location of Roots
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon