Without solving the following quadratic equation, find the value of ‘m’ for which the given equation has real & equal roots. ² + 2( – 1) + ( + 5) = 0

5, –2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5, –1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

–4, 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4, –1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

4, 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D
4, –1

Suggest Corrections

Similar questions

x^{2} - 5 x - 10 = 0

x^{2} + (p - 3) x + p = 0

The value of p for which the quadratic equation $2 p x^{2} + 6 x + 5 = 0$ has real and distinct roots is :

k x^{2} - 2 \sqrt{5} x + 4 = 0

Without solving the following quadratic equation, find ‘’ for which the roots are equal.

² – 4 + 3 = 0

p x^{2} - 4 x + 3 = 0

Join BYJU'S Learning Program