Question

Without trigonometric table, evaluate $\frac{\sec {41}^o}{\text{cosec}{49}^o}$

• A. $0$
• B. $1$
• C. $2$
• D. $-2$

Answer 1

Answer: (B)

$1$

Given

$\frac{\sec {41}^o}{\csc {49}^o}$

$=\frac{\sec \left({90}^o-{49}^o\right)}{\csc {49}^o}$

$=\frac{\csc {49}^o}{\csc {49}^o}$ as we know $\sec ({90}^o-\theta )=\csc \theta$

$=1$

Hence $1$ is the answer