Without using log table prove that 25-log103- 12

[ 2 / 5 lt;log _ 10 ^ 3 lt; 1 / 2 #160;; 0.4 lt;0.47 lt;5 ] ...

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Without using log table prove that $\frac{2}{5} < {log}_{10} 3 < \frac{1}{2}$

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\frac{2}{5} < l o g_{10} 3 < \frac{1}{2}

2 {log}_{10} 5 + {log}_{10} 5 - \frac{1}{2} {log}_{10} 4

{log}_{10} 3 = 0.4771212

{log}_{10} 9, {log}_{10} \sqrt{3}, log (\frac{1}{9})

{log}_{10} (0.3)

{log}_{2} {log}_{2} {log}_{2} 16

{log}_{10} 5 = 0.6990,

{log}_{10} 25, {log}_{10} 4 \sqrt{625}, {log}_{10} (\frac{1}{3125})

log 5000

{log}_{10} 2

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