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Byju's Answer
Standard XII
Mathematics
Trigonometric Ratios of Compound Angles
Without using...
Question
Without using trigonometric table, evaluate :
2
3
c
o
s
e
c
2
58
o
−
2
3
c
o
t
58
o
t
a
n
32
o
−
5
3
t
a
n
13
o
t
a
n
37
o
t
a
n
45
o
t
a
n
53
o
t
a
n
77
o
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Solution
2
3
c
o
s
e
c
2
58
o
−
2
3
c
o
t
58
o
t
a
n
32
o
−
5
3
t
a
n
13
o
t
a
n
37
o
t
a
n
45
o
t
a
n
53
o
t
a
n
77
o
=
2
3
c
o
s
e
c
2
58
o
−
2
3
c
o
t
58
o
t
a
n
(
90
o
−
58
o
)
−
5
3
t
a
n
13
o
t
a
n
37
o
t
a
n
45
o
t
a
n
(
90
o
−
37
o
)
t
a
n
(
90
o
−
13
o
)
=
2
3
c
o
s
e
c
2
58
o
−
2
3
c
o
t
2
58
o
−
5
3
t
a
n
13
o
t
a
n
37
o
t
a
n
45
o
c
o
t
37
o
c
o
t
13
o
=
2
3
(
c
o
s
e
c
2
58
o
−
c
o
t
2
58
o
)
−
5
3
t
a
n
13
o
t
a
n
37
o
×
1
×
1
t
a
n
37
o
×
1
t
a
n
13
o
=
2
3
×
1
−
5
3
=
−
1
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