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Byju's Answer
Standard XII
Mathematics
Basic Trigonometric Identities
Without using...
Question
Without using trigonometric tables, evaluate the following :
sec
41
o
.
sin
49
o
+
cos
49
o
csc
41
o
−
2
√
3
(
tan
20
o
.
tan
60
o
.
tan
70
o
)
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Solution
sec
41
∘
sin
49
∘
+
cos
49
∘
csc
41
∘
−
2
√
3
(
tan
20
∘
tan
60
∘
tan
70
∘
)
=
sec
41
∘
sin
(
90
−
41
)
+
cos
41
∘
csc
(
90
−
49
)
−
2
√
3
(
tan
(
90
−
70
)
√
3
tan
70
∘
)
=
sec
41
∘
cos
41
∘
+
cos
41
∘
sec
41
∘
−
2
√
3
(
cot
70
∘
√
3
tan
70
∘
)
=
1
+
1
−
2
=
0
using reciprocal relations of trigonometry.
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