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Standard XII

Physics

Relative Velocity in 2D

wo particles ...

Question

wo particles A and B are placed as shown in the figure. The particle A, on the top of tower, is projected horizontally with a velocity u and the B is projected along the surface towards the tower simultaneously. If particles meet each other, then the speed of projection of particle B is [Ignore friction]

d \sqrt{\frac{g}{2 H}} - u

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d \sqrt{\frac{g}{2 H}}

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d \sqrt{\frac{g}{2 H}} + u

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u

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Solution

The correct option is A $d \sqrt{\frac{g}{2 H}} - u$
Since they meet, $(u + V_{B}) T = d$
$V_{B} = \frac{d}{T} - u$
$= d \sqrt{\frac{g}{2 H}} - u$

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The correct option is A d√g2H−uSince they meet, (u+VB)T=d VB=dT−u =d√g2H−u

The correct option is A $d \sqrt{\frac{g}{2 H}} - u$
Since they meet, $(u + V_{B}) T = d$
$V_{B} = \frac{d}{T} - u$
$= d \sqrt{\frac{g}{2 H}} - u$