The correct option is D a+c=91b
We have 11 letters
A,A,E,E,E,J,D,D,V,N,C,
If all vowels are together, then we will put them in a box and consider them as a single object. Now, we have 6 consonants and 1 object (all vovels). So, arrangements of the 7 objects =7!2! (D occurs twice)
Internal arrangement of the vowels
=5!2!3!⇒a=7!2!×5!2!3!
For b, First we will arrange 6 consonants. To make them seperated we need to five 5 spaces among them by arranging vowels.
Arrangement of consonants
=6!2!
Arrangement of vowels
=5!2!3!b=6!2!×5!2!3!
For c, there are three cases
When the end letters are A,A
Number of words formed
=9!2!3!
When the end letters are E,E
Number of words formed
=9!2!2!
When the end letters are E,A
Number of words formed
=9!2!2!×2!
∴c=9!2!3!+9!2!2!+9!2!