Question

Work done by air when it expands from $50$L to $150$L at a constant pressure of $2$ atmosphere.

• A. $2\times {10}^4$J
• B. $2\times 100$J
• C. $2\times {10}^{11}$J
• D. $2\times {10}^{15}$J

Answer 1

The correct option is A $2\times {10}^4$J

Work done
$W=p(V_2-V_1)$
Given, $p=2\times {10}^{5}N/m^2,V_1=50\times {10}^{-3}{m}^3$,
$V_2=150\times {10}^{-3}{m}^3$
$\therefore W=2\times {10}^5(150-50){10}^{-3}$
$W=2\times {10}^5\times 100\times {10}^{-3}$
$W=2\times {10}^4$J.