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Question

Work done by an individual force is zero if the work done by the resultant force is also zero

A
True
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B
False
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Solution

The correct option is B False
Let F1,F2......Fn be n non zero force vectors.

Work done by the forces=(F1+F2.......+Fn).d=F1.d+F2.d+......Fn.d

Now in the equation
LHS can ne zero when the vector sum of all forces =0,
But RHS(individual work done) needn't be zero.

For example,
Suppose two forces be 2i, -2i,
And displacement be 3i,

Then
Total work done=(-2i+2i).3i=0$

Individual work done,
W2i=6J

W2i=6J

Hence the statement is false.

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