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Question

Work Done in reversible adiabatic process is given by:

A
2.303 RT logV2V1
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B
nR(γ1)(T2T1)
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C
2.303 RT logV1V2
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D
None of these
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Solution

The correct option is B nR(γ1)(T2T1)
We know, from first law, ΔU=q+w.
For adibatic process, q=0.
Also ΔU = nCvdT and w = ΔU = nR(γ1)(T2T1).
These are the derived formula for Wrev in adiabatic process.

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