Work Done in reversible adiabatic process is given by:
A
2.303RTlogV2V1
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B
nR(γ−1)(T2−T1)
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C
2.303RTlogV1V2
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D
None of these
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Solution
The correct option is BnR(γ−1)(T2−T1) We know, from first law, ΔU=q+w. For adibatic process, q=0. Also ΔU = nCvdT and w = ΔU = nR(γ−1)(T2−T1). These are the derived formula for Wrev in adiabatic process.