Work done in the cyclic process shown in figure is :
A
4P0V0
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B
−4P0V0
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C
−227P0V0
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D
−13P0V0
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Solution
The correct option is A−227P0V0 Workdone in cyclic process is in anticlockwise direction is negative of area of cyclic process =π(Po)(Vo) [∴ Area of ellipse =πab] So, workdone in cyclic process =−(227)PoVo[∵π=227]