Work done in time l on a body of mass n which is accelerated from rest to a aspeed v in time t1 as a function of time t is given by:
A
12(mvt1)t2
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B
m(mvt1)t2
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C
12(mvt1)2t2
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D
12mv2(tt1)2
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Solution
The correct option is D12mv2(tt1)2 Acceleration is a constant given by: a=v−0t1 Force acting on it = ma =mvt1 displacement is given by: s=12at2 s=12vt1t2 i.e Work done =F.s=12mv2(tt1)2 Option D is correct.