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Question

Work done on a liquid drop to increase its radius from 3 cm to 5 cm is π×104 J. Find the surface tension of liquid.

A
18 N/m
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B
14 N/m
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C
164 N/m
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D
132 N/m
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Solution

The correct option is C 164 N/m
As we know,
Liquid drop has only one layer.
Work done in formation of liquid drop;
W=4πT(r2fr2i)
where,
Surface tension of liquid is T
Final radius of liquid drop,rf=5×102 m
Initial radius of liquid drop,ri=3×102 m

4π×T×(0.0520.032)=π×104 J
T=164 N/m

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